Jerome

Ok, but this is a question for the asp.net forum no?

Hi,I don't get what you want... If you want dependant dropdown boxes, you need to refresh your page using the javascript submit function... Just explain a little more. Thanks.

Hi there!Did you started to write your page yet? Could paste some of your code so we can start with something!

hi!Try this :

Dim timeNowtimeNow = nowResponse.Write(DateAdd("d",1,timeNow))

I'm adding 1 day to the actual time. You can switch with h (hours), m (months), n (minutes), s (seconds) and yyyy (years)!

ok, post your code and the error message!

There you go : http://w3schools.invisionzone.com/index.php?showtopic=269

What I am trying to do is I have a database that has percentages for the values.  And when I display the data if the number from the database is greater than 100% I want it to turn red and if it is less than 100% I want it to turn green.  Is it even possible?

<{POST_SNAPBACK}>

Yes it's possible,To display your datas from your access database, I assume you will use a loop condition. During the loop you will just have to check for every value if it's greater or smaller than 100. According to the result, you put the data in red or in green... Let's say you have a RecordSet object called Rs :

Do While Not Rs.EOF If Rs("yourData") > 100 Then     Response.Write("<font color=""red"">" & Rs("yourData") & "</font><br>")Else     Response.Write("<font color=""green"">" & Rs("yourData") & "</font><br>")End IfRs.MoveNextLoop

What kind of data are you working with? What do you want to mesure with 100%? The length of your cell? of your table?

Hi,What exactly are you planning to do working from another computer? Just read, update and delete data from your database? Because if that is the case you don't need the install sql server... Try to explain with more detail your question.

Ok, just call the function where you need to use your random number :

<DIV STYLE="position:absolute; LEFT: <%=RandomNumber(5,600)%>px; TOP: <%=RandomNumber(5,600)%>pt">Hello</div>

Yes, you just need to add your condition :

If Len(yourData) > 100 Then       Response.Write("<font color=""red"">" & yourData & "</font>")Else      Response.Write(yourData)End If

If your data has more than 100 caracters, then it is displayed in red, else in the (default) black.

.. I can't add the first comment through my form.. It's the same error again..

<{POST_SNAPBACK}>

I don't get the problem... Did you try the loop I gave you, what error do you get?

Can you try to rewrite the code once again?

<{POST_SNAPBACK}>

No, this time we will do it together, otherwise I feel you won't understand what you do.

Hi damini,When a user logs in with a correct login and password then you can assign him a session (default time 20 minutes). Then, on the top of each of your asp pages you should put an include file called for e.g. validate_user.aspIn that file you will verify if the user that is trying to open any page of your site, has an active session, if it's not the case then your redirect him to the default.asp. Got it?Here is the explanation concerning the session object : http://www.w3schools.com/asp/asp_sessions.aspIn your validate_user.asp file you can put something like :

<%If Len(Trim(session("userID"))) <= 0 Then    Response.Redirect ("../default.asp")End If%>

You're welcome!Was it usefull?

I don't think you can query directly a .csv file... but what you still can do is save the .csv as a .xls file and then query this excel file... like here : http://w3schools.invisionzone.com/index.php?showtopic=612

HiHere you have a function that receives two parameters (highest and lowest number), the "Do Untill" loop provides you a random number between those two parameters, then you just have to put those values into your top and left variables.

<%Function RandomNumber(intLowestNumber,intHighestNumber)      Do Until (RandomNumber >= intLowestNumber) And (RandomNumber <= intHighestNumber)      Randomize      RandomNumber = Int(Rnd * intHighestNumber) + 1	LoopEnd FunctionleftRndNumber = RandomNumber(5,600)topRndNumber = RandomNumber(5,600)%>

Happy programming

Ok Rob, I don't see what's wrong... I created a table like yours and used the query I showed you and there is no problem... Paste your code and the structure of your table (name, fields,...)

Thank you Chocolate!And you already are hable to change the admin of the forum or is it for in a while?

Hi,Now that we have such a nice moderating team, I really think it's necesary to let the users know when a problem is solved (and when it is not)... Here is an example from a french programming forum, you can see that when a problem has been solved, it's written ("[resolu]") next to title of the problem posted... So that you don't have to check every post, it's maybe not too important for the moment, but when you get more than 1000 post in one day (like this french forum does), it becomes really interesting...I would like to have your opinion on this.

I don't get it...Wich sql statement are you using? Something like this :

SELECT TOP 4 * FROM yourDataBase

Denny,You are right, the problem is in your loop... your are asking the cursor to go throught the recordset untill he comes to the End Of File (EOF). If the table contains any value, there is no problem. But if it's empty, it just doesn't find any End Of File, and it keeps looking and looking untill you get an error...Instead, try to use a "Do While" loop like this :

<%'...Do While Not rs.EOF And Not rs.BOF  Response.Write(rs("ime") & " " & rs("komentar") & " " & rs("vrijeme"))rs.MoveNextLoop'... %>

Pls, paste your code

That's why it's good to have some competition, don't you think? Good posting and happy programming

Here you go : http://www.ajaxtoolbox.com/http://somedirection.com/index.php/2005/03/25/using-ajax/http://www.askdavetaylor.com/what_is_ajax.htmlhttp://www.sematopia.com/?p=34...

Good idea!