Dam this form

[Obi1-Cannabis]

i'm working with javascript and php to make a form that for each product of a DB has a diferent valuehow can i do this without having to use a submit button? because the onclick="document.form.submit();", where 'form' is a php variable doesn't work however the name of the form can be a php variable.please help

[aspnetguy]

If there is only one form on the page use the following code it won't matter what the form name is

onclick="document.forms[0].submit();

or

onclick="document.getElementsByTagName('form')[0].submit();

[Obi1-Cannabis]

If there is only one form on the page use the following code it won't matter what the form name is

onclick="document.forms[0].submit();

or

onclick="document.getElementsByTagName('form')[0].submit();

what if i have more then one form?

[aspnetguy]

to refer to a specific form on a page...[0] refers to the first form on the page, [1] the second, [2] the third, etc etcJust change the index number to reference the correct form

[MrAdam]

onclick="document.forms[0].submit();

...

onclick="document.forms[1].submit();

goes up for each form on the page in the order they appear.

[Obi1-Cannabis]

That would work fine if my DB had only one element, but that's not the case...

foreach($tipop as $k2=>$v2 ){if ($tipop[$k2]['IDFamilia'] == $familia[$k]['ID']){	$this->idt=$tipop[$k2]['ID'];	print"  <tr> 		<form method='Post' action='index.php' name='".$k2."' id='".$k2."'>			<input type='hidden' name='comando' value='escolhi'>			<input type='hidden' name='idt' value='".$tipop[$k2]['ID']."'>		</form>			<td width='200' align='left' onclick=\"document.".$k2.".submit();\"style=\" cursor:pointer; cursor:hand;\" onmouseover=\"bgColor='lightyellow';\" onmouseout=\"bgColor='white';\">		".$tipop[$k2]['Descricao']."							</td>						   </tr>";	}}

This is what's not working...

[jnutty1]

That would work fine if my DB had only one element, but that's not the case...

foreach($tipop as $k2=>$v2 ){if ($tipop[$k2]['IDFamilia'] == $familia[$k]['ID']){	$this->idt=$tipop[$k2]['ID'];	print"  <tr> 		<form method='Post' action='index.php' name='".$k2."' id='".$k2."'>			<input type='hidden' name='comando' value='escolhi'>			<input type='hidden' name='idt' value='".$tipop[$k2]['ID']."'>		</form>			<td width='200' align='left' onclick=\"document.".$k2.".submit();\"style=\" cursor:pointer; cursor:hand;\" onmouseover=\"bgColor='lightyellow';\" onmouseout=\"bgColor='white';\">		".$tipop[$k2]['Descricao']."							</td>						   </tr>";	}}

This is what's not working...

Obi1,The code you have will work as long as the value in $k2 will create a valid form name. If $k2 contains spaces, special characters, etc., it will fail.

[Obi1-Cannabis]

Obi1,The code you have will work as long as the value in $k2 will create a valid form name. If $k2 contains spaces, special characters, etc., it will fail.

Yes i found the problem already, the thing is that i was trying to use integer for the name. but thanks anyway.