passing php from one page to another in a url

[JLG]

I'm really not good at PHP or JavaScript so i'm hoping someone will be able to cure this problem really easily. I've done searches but even this simple stuff is a bit over my head.I have a menu which when clicked on shows submenu item underneith. When a sub menu item is clicked on it goes to another page (without a menu on), on that page i have a link saying back. When they go back to the original page with the menu on i would like the sub menu to still be shown.at the moment i have this piece of code on the menu page:

<?phpif(!isset($Menu)) {$Menu = "1";} print "<script language=\"javascript1.2\" type=\"text/javascript\">toggleview('menu".$Menu."')</script>\n";?>

this code opens the submenu when i go to the page but i only want it open the submenu when /intro.php?Menu=1 is in the URL not when it is just /intro.php (or anything else).I can't put links up cuz i'm on an internal intranet system, i hope this make sense to someone. Please help.

[JLG]

Doesn't matter i cured it with:<?phpif(isset($_GET['Menu'])) { print "<script language=\"javascript1.2\" type=\"text/javascript\">toggleview('menu".$_GET['Menu']."')</script>\n";}?>I was just being thick.

[zanfranceschi]

remember you can use $_REQUEST[] instead of $_GET. I'm not sure, but i guess $_GET only works with forms...

[JLG]

I'll remember that for next time but for now $_GET works and it's not using any forms just the url. Cheers.