son Posted July 25, 2008 Share Posted July 25, 2008 I have a script and cannot get my head around the following: if (mysqli_num_rows($result) == 0) { $number = 1; echo "\n<!-- number does not exist -->\n"; } In the database we have an entry for the variable $number = 1 as such. It is a default that shows when no other existing option is selected. Why would we assign 1 to $number and then give error message? If we assign an existing value, then surely the message will never come up. The script is working just fine, I just try to understand (has been developed by someone who knows more than I do)... I hope I make senseSon Link to comment Share on other sites More sharing options...
Synook Posted July 25, 2008 Share Posted July 25, 2008 Well, the error is commented out (in the HTML) - maybe the coder just wanted to use that statement to debug... Link to comment Share on other sites More sharing options...
son Posted July 25, 2008 Author Share Posted July 25, 2008 Well, the error is commented out (in the HTML) - maybe the coder just wanted to use that statement to debug...That makes sense. Maybe he just had it in to start off with and then commented it out later on adding the assignment line...Thanks,Son Link to comment Share on other sites More sharing options...
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