I Have A Problem In Updation Please Solve

[furqan219]

hi this is code of form in which i have populated data from databse.

<form action="update.php" method="post"><input type="text" name="userdate" value="<?= $b ?>" /> <input type="submit" name="subjoin" value="Update"></form>

and update.php

 $c= $_POST["$b"];echo "value".$c; //its not working

but it does not post a value

[smerny]

the data is stored under the name... you need to either change the name from "userdate" to "b" in the form AND change $_POST["$b"] to $_POST["b"] in update.phpor change $_POST["$b"] to $_POST["userdate"] in update.php

Edited June 9, 2009 by smerny

[furqan219]

I do this but when i click update button it shows blank page in result of update.php

[smerny]

then there is another problem, can you show more of the update.php page?

[furqan219]

this is a code

<?php$con = mysql_connect("localhost","xxx","xxx");if (!$con)  {  die('Could not connect: ' . mysql_error());  }mysql_select_db("onm", $con);$c= $_POST['name'];echo $c;echo "0play";/*mysql_query("UPDATE SitePInfo SET Age = '36'WHERE FirstName = 'Peter' AND LastName = 'Griffin'");*/mysql_close($con); ?>

[furqan219]

<?$con = mysql_connect("localhost","xxxx","xxxx");if (!$con)  {  die('Could not connect: ' . mysql_error());  }mysql_select_db("onm", $con);$result = mysql_query("SELECT * FROM sitepinfoWHERE SiteId='C-SIL-4441' "); // I just get one value at this timewhile($row = mysql_fetch_array($result))  {  echo "<table cellpadding=2 cellspacing=2 width=100%><tr></tr>";  echo "<tr>";  echo "<th bgcolor=#5D9BCC >SiteID</th>";  echo "<td bgcolor=#FEE9A9>" . $row['SiteId'] . "</td>"; // show value in cell  $b =$row['SiteId']; // store value in $b        echo "</tr>";   }echo "</table>";mysql_close($con);?><form action="update.php" method="post" name="frmmain" id="frmmain"><!-- <input name="hdnSiteID" type="text" id="hdnSiteID" value="<?php print($b);?>" />--><input type="text" name="name" value="<?= $b ?>" /> <input type="submit" name="subjoin" value="Update"></form>

[smerny]

did you change form to this then :

<form action="update.php" method="post"><input type="text" name="name" value="<?= $b ?>" /><input type="submit" name="subjoin" value="Update"></form>

EDIT: nvm i see you posted the form

Edited June 9, 2009 by smerny

[furqan219]

I am new to PHP but I really want to learn new technique.I have tried many codes but its not working.Also I have no idea how to update databse using this method.

[smerny]

<input type="text" name="name" value="<?php echo $b; ?>" />and... the update page should not be "blank" as far as i can tell :S(should at the very least see "0play" or an error msg)

Edited June 9, 2009 by smerny

[furqan219]

Can I send code of both pages again?

[furqan219]

Now its working Friendwith this code

if(!empty($_POST["name"])){$c= $_POST["name"];echo $c; //its working}

[furqan219]

thank you so much, i have another big issue.