Output All Nodes In Order

[Digga]

HiPlease bear with me, I've just dipped my toe in the XSLT waters and regardless what I do I cannot output the following XML in order, I always get grouped nodes - categories then fields.Here's a sample of the XML:

<form>  <category name="Content" />  <field column="QueryName" value="1" />  <category name="Content filter" />  <field column="OrderBy" value="123" />  <field column="TransformationName" value="45" />  <field column="DetailTransformationName" value="76" />  <field column="AlternatingTransformationName" value="88" />  <category name="Layout" />  <field column="RepeatColumns" value="44" />  <field column="RepeatDirection" value="36" />  <field column="RepeatLayout" value="77" /></form>

And here's the output I would like to see:Category Name: ContentField: Column: QueryName Value: 1Category Name: Content filterField: Column: OrderBy Value: 123Field: Column: TransformationName Value: 45Etc.The output is a sample and would get me going in the right direction. I just need to process each in the order found in the XML file.Many thanks in advance for any advice and guidance for this newbie would be very much appreciated.Digga

[Martin Honnen]

The nodes are processed in document order anyway, unless you used xsl:sort. So simply write templates for the category and field elements outputting what you want:

<xsl:stylesheet  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"  version="1.0">    <xsl:strip-space elements="*"/>  <xsl:output method="text"/>    <xsl:template match="form/category">	<xsl:value-of select="concat('Category Name: ', @name, '')"/>  </xsl:template>    <xsl:template match="form/field">	<xsl:value-of select="concat('Field: Column: ', @column, ' Value: ', @value, '')"/>  </xsl:template> </xsl:stylesheet>

Note: the '' in the code sample should be '& # 1 0;', only without the spaces.

[Digga]

Thanks Martin, I was obviously trying this with a too complicated approach.