Assigning Key-Value Pairs to a Variable-Variable Array

[iwato]

Background: The following function is suppose to find duplicated values in an input array and return the corresponding elements grouped together in subarrays of an output array. The function fails when I try to turn add elements to a variable-variable array via the brackets operator. The following statement is rejected with the following error message:Statement: $$count_val[$key] = $val;Error Message: Uninitialized string offsetQuestion: How do you add elements to a variable-variable array?

<?php	function array_dupl_keys($array){		$count= array_flip(array_count_values($array));		if (array_key_exists(1, $count)) {			foreach ($count as $key=>$val) {				if ($key == 1) unset($count[$key]);			}		}		$intersect = (array_intersect($array, $count));		foreach($count as $count_val) {			$$count_val = array();			foreach($intersect as $key=>$val) {				if ($count_val == $val) {					$$count_val[$key] = $val;				}			}			$summary[$count_val] = $$count_val;		}					return $summary;			}?>

Roddy

[iwato]

The following statement is rejected with the following error message:Statement: $$count_val[$key] = $val;Error Message: Uninitialized string offset

Solution: I still do not understand the above error message, but with a little trial and error the following adjustment has proven successful, and the function performs as intended.${$count_val}[$key] = $val;Roddy

[iwato]

<?php	function array_dupl_keys($array){		$count= array_flip(array_count_values($array));		if (array_key_exists(1, $count)) {			foreach ($count as $key=>$val) {				if ($key == 1) unset($count[$key]);			}		}		$intersect = (array_intersect($array, $count));		foreach($count as $count_val) {			$$count_val = array();			foreach($intersect as $key=>$val) {				if ($count_val == $val) {					${$count_val}[$key] = $val;				}			}			$summary[$count_val] = $$count_val;		}					return $summary;			}?>

For a, perhaps, obvious reason -- i.e. use of the array_flip() function -- the now ready array_dupl_keys() function only works with arrays containing values that can serve as valid keys. As such, arrays containing objects, subarrays, and the like, will fail.Roddy