BigD Posted August 13, 2012 Share Posted August 13, 2012 In the following code why gdate has the value of 12-08-13? could that cause sql error? or could the picture field(which is a thumb nail picture) cause the error?I have used the date("y-m-d") before and I was getting 2012-08-12. $gdate = date("y-m-d"); echo "gdate is $gdate"; $query = "INSERT INTO graduate(fname, lname, phone, email, picture, startdate, ". "gdate, gender, stdid, classid, intid) values('$fname', '$lname', '$phone', '$email', ". "'$picture', '$startdate', '$gdate', '$gender', '$stdid', '$classid', '$intid')"; echo "insert grad SQL is $query"; $result = mysql_query($query); if ($result) { echo "<h2>Student $fname $lname graduated</h2>\n"; } else { echo "<h2>SQL error</h2>\n". mysql_error(); } Link to comment Share on other sites More sharing options...
BigD Posted August 13, 2012 Author Share Posted August 13, 2012 This is the result: gdate is 12-08-13insert grad SQL is INSERT INTO graduate(fname, lname, phone, email, picture, startdate, gdate, gender, stdid, classid, intid) values('F', 'L', '111-222-3333', 'lf@gmail.com', 'JFIF>CREATOR: gd-jpeg v1.0 (using IJG JPEG v62), default quality C $.' ",#(7),01444'9=82<.342C 2!!22222222222222222222222222222222222222222222222222 Link to comment Share on other sites More sharing options...
birbal Posted August 13, 2012 Share Posted August 13, 2012 sql error will tell where the error is. if gdate is date type the format is YYYY-MM-DD. if picture column is location of thumbnail it should be char/varchar or other textutal type. if it is the image itself it has to be stored as binary type Link to comment Share on other sites More sharing options...
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