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Use split semicolons within xslt


Johan1974
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Hello is it possible to use xslt to go from Code:<XML> <TAG1>tag1value1;tag1value2</TAG1> <TAG2>tag2value1;tag2value2</TAG2> </XML>To thisCode:<XML> <LINE> <TAG1>tag1value1</TAG1> <TAG2>tag2value1</TAG2> </LINE> <LINE> <TAG1>tag1value2</TAG1> <TAG2>tag2value2</TAG2> </LINE></XML>Any help would be most appreciated.Johan

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  • 1 month later...

Try this one with 2.0:<?xml version="1.0" ?><xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"><xsl:template match="/"> <XML> <xsl:apply-templates/> </XML></xsl:template> <xsl:template match="TAG1 | TAG2"> <LINE> <xsl:analyze-string select="text()" regex="([a-zA-Z0-9]+)(;)"> <xsl:matching-substring> <xsl:choose> <xsl:when test=".[position() = 1]"> <TAG1><xsl:value-of select="replace(.,';','')"/></TAG1> </xsl:when> <xsl:when test=".[position() = last()]"> <TAG2><xsl:value-of select="replace(.,';','')"/></TAG2> </xsl:when> <xsl:otherwise> <TAG1><xsl:value-of select="replace(.,';','')"/></TAG1> </xsl:otherwise> </xsl:choose> </xsl:matching-substring> <xsl:non-matching-substring> <TAG2><xsl:value-of select="replace(.,';','')"/></TAG2> </xsl:non-matching-substring> </xsl:analyze-string> </LINE> </xsl:template></xsl:stylesheet>

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