xquery help

[dmllc]

http://mlb.mlb.com/partnerxml/gen/news/rss/nym.xmli am trying to select the items that were published on the same date but i am not sure how to do this due to the format of the pubDate element. currently i am simply using <xsl:value-of select="pubDate"/>. also, is there a way to display the pubDate without the time string?

[boen_robot]

I don't think XSLT provides dynamical functions to check if a string matches the current date. I think there was some XPath 2.0 function that formats the date so you could then check it, but that's still not supported anywhere.I see that you're using some exslt.org extensions though, so I guess that's just another one you'll need.As for how to select the date without the hour, you could use the substring() function. It would requre a lot of substring() functions if you want to reformat the date though.

[dmllc]

i think i found a way to accomplish what i want, but the xpath function is not working like i thought it would.<xsl:value-of select="substring('pubDate',1,15)" /> is returning the string pubDate instead of the first 15 characters of a xml pubDate value: Thu, 01 Jun 2006 15:45:00 EDTwhat is the correct xpath function to display Thu, 01 Jun 2006 15:45:00 EDT as Thu, 01 Jun 2006?

[dooberry]

get rid of the speechmarks around pubdate:

<xsl:value-of select="substring(pubDate,1,15)" />

If you use speechmarks inside an xpath expression/function then xpath thinks that you have put a value between the speechmarks, not the name of the element you need to look at.To see what I mean try:

<xsl:value-of select="pubDate" />

and then try:

<xsl:value-of select="'pubDate'" />

[dmllc]

thx!