Photo doesn't display

[jpergega]

Hi

 

I am trying to fetch photos from the database but it doesn't show on the website page:

 

PHP -

 

function getImage(){

$query = "SELECT * FROM imgLib WHERE id=$_SESSION['id']";

$result = mysqli_query($con, $query);

while($row = mysqli_fetch_assoc($result)){

echo $row['img'];

}

}

HTML -

<img class="img-responsive" src="<?php getImage(); ?>" >

Result on Website page -

see attachment

Thanks

[Ingolme]

Have you checked the source code of the page to see what is actually in the src attribute?

 

I assume either an error message, an empty string or multiple filenames.

[jpergega]

I only can see this error message :

 

Failed to load resource: the server responded with a status of 403 (Forbidden)

[Ingolme]

That sounds like a message in the console. I was asking about the HTML. If you right click and select "View source" what does the <img> tag look like?

[jpergega]

Sorry this is what I got:

<a class="thumbnail" href="#">

<img class="img-responsive" src="<?php getImage(); ?>" >

</a>

[Ingolme]

It sounds like PHP isn't being executed.

 

At least two conditions need to be met for PHP to work:

1. It's running on a server that can execute PHP
2. The file has a .php extension, not .html.

[jpergega]

Thanks for this

 

I am using WAMP Server

I changed my files' extension to .php and is now giving me error message inside the image frame says: call to undefined function functionName()

 

Here is how I call the function :

<img class="img-responsive" src="<?php include 'functions.php'; getImage(); ?>" >

Edited February 8, 2015 by jpergega

[Ingolme]

I don't think I've seen all your code.

 

Does the error message specifically say "functionName()" or does it say "getImage()"?

[jpergega]

It says getImage()

[funbinod]

have u included functions.php at the beginning of the page? if u haven't, I think, removing the functions.php from img tag and placing it at the beginning of the page can solve the problem. u doesn't need to include inside img tag.