vmars316 Posted June 18, 2015 Share Posted June 18, 2015 Hello & Thanks , I created a freeware program (myFavs) that creates an html page (myFavs.html) which has a bunch of dropDown menus . Each menu has a list of websites to click on . It works fine , except that when I click/select a link it reuses the same Tab as the myFavs.html I did the clicking on . But what I want to do , is to open up a new Tab for the clicked-on link . I believe all I need to do is to change the <select onchange= value . <select style="width:200px; font:14px Arial Black; color:rgb(0,0,0); background-color:rgb(231,169,126);" name="menu" onchange="window.open(this.options[this.selectedIndex].value,'_top')"> The part I need to change is this: onchange="window.open(this.options[this.selectedIndex].value,'_top')" To leave the myFavs.html open , AND open a New Window for the link clicked-on , what should that 'onchange=' be changed into ? Here is what the BuiltPage looks like: http://www.vmars316.com/ShowMe/MyIndex.html Thanks...Vern . Link to comment Share on other sites More sharing options...
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