What's wrong with this code snipet?

[jumpenjuhosaphat]

  else  {	$result = mysql_query("SELECT * FROM user");	while($row = mysql_fetch_array($result))	{	  if($row['id']==$_COOKIE["user"])		{		  $username=$row['username'];		}	}	include("body.php");  }

For some reason the variable $username isn't being set when this code returns true. Sorry if it's an obvious answer, I'm a newbie.

[jlhaslip]

Try this:

else  {	$result = mysql_query("SELECT * FROM user");	while($row = mysql_fetch_array($result))	{	  if($row['id']==$_COOKIE["user"])		{print_r($row);print_r($cookie);		  $username=$row['username'];		}	}	include("body.php");  }

This should print the array values for debugging.*editted*changed the location of the print _r()'s

[jumpenjuhosaphat]

Okay, I got if figured out. For some reason, on my server, you have to use $_POST["username"] instead of $username. I knew that, but I seemed to have forgotten it when coding this bit of code.

[skym]

The reason for that is http://php.net/register_globals It's best to have it disabled.