is_numeric and getType

[ZeroShade]

I need to use a conditional statement to check if a number is an integer and that it is also even. I've never used the getType or is_numeric inside a conditional statement before. Can somebody help me out?

[jlhaslip]

http://php.net/

[ZeroShade]

http://php.net/

I've searched the site but I am unable to find as to how to put it into a conditional statement.

[ZeroShade]

Is it something like this:$number = 5;if(is_numeric($number) AND getType($number))echo "<br />The number ", $number, " is even.";elseecho "<br />The number ", $number, " is odd.";???

[jesh]

I don't know about getType, but you might try the modulus operator (%) which, if you didn't already know, returns the remainder of one number divided into another number. For example, 5 % 2 == 1 because, when you divide 2 into 5, there is a remainder of 1. You can use this to get whether a number is even or not. An odd number % 2 will always return 1 whereas an even number will always return 0.

$number = 5if(is_numeric($number) AND ($number % 2 == 0)){	echo "<br />The number ", $number, " is even.";}else{	echo "<br />The number ", $number, " is odd.";}

[ZeroShade]

I thought the is_numeric() function returns if the number is even or not?

[Nakor]

It does. What he is saying is that you can use the modulus operator. The only issue with the code posted by jesh is that it will return saying that the number is odd if you input something that is not a number. You can catch that easily with an else if.

[pulpfiction]

is_numeric() finds whether a variable is a number or a numeric stringhttp://us3.php.net/is_numeric

[pulpfiction]

Slightly modified.....

$number = 5if(is_numeric($number) {	if ($number % 2 == 0)   {	   echo "<br />The number ", $number, " is even.";   }   else   {	   echo "<br />The number ", $number, " is odd.";   }else{	echo "Not a Number";}

[ZeroShade]

Ok... i understand now... thanks!!

[jesh]

Slightly modified.....

Nice catch...

[justsomeguy]

is_numeric is only used to test if a string is a numeric string. It returns true if the string can be parsed as either an integer or a float. If you want to check if your variable is specifically an integer (and not an integer string, btw), you can use this:

if(gettype($number) == "integer") {

If you want to check if the variable is an integer string, you can use this:

if(intval($number) == $number) {