Obi1-Cannabis

Nevermind, solved it.

ah now i got ya... what's the browser your using?I'm in another computer and it's also ok here

i have the ADOdb connection in the constructor of a class in a variable $conn but when i try to use it in another function forexample $var=$conn->GetAll("Select * from table where id='$id'") it gives me this error in the output:Fatal error: Call to a member function on a non-object in C:\Trabalhos\Apache\estagio\teste\classes\class.php on line 24can anyone explain?

i'm not sure if this will help you: http://www.desilva.biz/php/bbcode1.html

maybe if you try to do a counter that counts the number of lines of the menu in the main code and give a diferent class in css for that 5th line...but i don't now i'm quite new at this and i'm not even sure if i've got your problem right...

click it to see a bit bigger

in my browser there's no white line i would send a print screen but i have no where to upload it

I don't see what is the problem it seems to be like all the others...

imagine i'am creating a site for blind people...does this type of media works on any browser?do i need something special to make it work?and what about the language, is it only available in english? or is it possible to select another language like portuguese for example?>>>Obi1

Yes i found the problem already, the thing is that i was trying to use integer for the name. but thanks anyway.

Finnaly solved it using the way i was before, the problem was that i was trying to use an integer variable for form's id if i use a string it works.To think i took 3 days to see the problem lol.

That would work fine if my DB had only one element, but that's not the case... foreach($tipop as $k2=>$v2 ){if ($tipop[$k2]['IDFamilia'] == $familia[$k]['ID']){ $this->idt=$tipop[$k2]['ID']; print" <tr> <form method='Post' action='index.php' name='".$k2."' id='".$k2."'> <input type='hidden' name='comando' value='escolhi'> <input type='hidden' name='idt' value='".$tipop[$k2]['ID']."'> </form> <td width='200' align='left' onclick=\"document.".$k2.".submit();\"style=\" cursor:pointer; cursor:hand;\" onmouseover=\"bgColor='lightyellow';\" onmouseout=\"bgColor='white';\"> ".$tipop[$k2]['Descricao']." </td> </tr>"; }} This is what's not working...

nah... nothing seems to wor here i've got to find another way to do this...

nope it dosn't work either i've tried it already. i also tried something like:<td width='200' align='left' onclick=\"document.forms[0].submit();>but since i have another form in the same page it doesn't work either...

what if i have more then one form?

it's not that i can't use a submit button, but it isn't very pleasant to see so i just wanted to use text from a table cell...<form method='Post' action='index.php' name='".$myForm."'><input type='hidden' name='comando' value='escolhi'><input type='hidden' name='idt' value='".$tipop[$k2]['ID']."'></form> <td width='200' align='left' onclick=\"document.".$myForm.".submit();\"style=\"cursor:pointer; cursor:hand\" onmouseover=\"bgColor='lightyellow';\" onmouseout=\"bgColor='white';\">".$type[$key]['Value']." </td>this one isn't working, tough the onmouseover and onmouseout are working.

i'm working on a form that for each product of a DB has a diferent valuehow can i do this without having to use a submit button? because the onclick="document.form.submit();", where 'form' is a php variable doesn't work however the name of the form can be a php variable.please help

i'm working with javascript and php to make a form that for each product of a DB has a diferent valuehow can i do this without having to use a submit button? because the onclick="document.form.submit();", where 'form' is a php variable doesn't work however the name of the form can be a php variable.please help

Do i have to make any function before i use an<td onClick="Document.Form.Submit">? if yes, does the form needs to be inside? it's not working for me...

Thank you it's working now.

Is it possible to force a link on php.my idea is: i have a form that takes me to another page but i want it to stay in the same if the fields are not complete, if they are wrong or if i already have that same data on my DB.how am i suposed to do such a thing?