gongpex

Hi, This to reply : This is my fix code : <?if($_SESSION['buy']){$count = count($_SESSION['buy']);for($x=0;$x<$count;$x++){$product_title = $_SESSION['buy'][$x][0];$product_price = $_SESSION['buy'][$x][1];$product_img = $_SESSION['buy'][$x][2];$product_id = $_SESSION['buy'][$x][3];$product_qty = $_SESSION['buy'][$x][4]; echo"$product_title<br />$product_price<br />$product_img<br />$product_qty<br /><br/>";}}else{echo"fail";}?> I had try new code, this my code : <?$product = array();$product[0] = $_SESSION['buy'][0];$product[1] = $_SESSION['buy'][1];$product[2] = $_SESSION['buy'][2];$product[3] = $_SESSION['buy'][3];$product[4] = $_SESSION['buy'][4]; $product = array_unique($product); if($_SESSION['buy']){$count = count($_SESSION['buy']);for($x=0;$x<$count;$x++){ $product_title = $product[$x][0]; $product_price = $product[$x][1]; $product_img = $product[$x][2];echo $product_title."<br />".$product_price."<br />".$product_img."<br /><br />";}}else{echo"fail";} Now I put array inside array, so that array_unique can be work, but if I delete code : $product = array_unique($product); It would be back like image on above (duplicated), But if I using this code , it's only show one product,and the other product cannot be shown. + About new code : Q : What's mistake from my code? + About fix code : This is still duplicated Q : from both of this code, which code that possible to be use so that when user buy product , it would be not duplicated? please help me Thanks

Sorry, I forgot to post something here, please see this code : <form method="post" action="buy.php"> <input type="text" value="<?$id1 = $product_id?>" style="display:none" name="test" /></div> <div class="pr" style="height:15px"><b style="font-size:14px"><?echo"$product_name";?></b></div> <div class="pr"><input type="submit" value="BUY NOW" /></div></form> //this is product 1<form method="post" action="buy.php"> <input type="text" value="<?$id2 = $product_id2;?>" style="display:none" name="test" /></div> <div class="pr" style="height:15px"><b style="font-size:14px"><?echo"$product_name2";?></b></div> <div class="pr"><input type="submit" value="BUY NOW" /></div></form> //this is product 2 When I click "BUY NOW" for every product (only once) it will shown like this : And if click "BUY NOW" twice or more , it will occurs like image on above. I will try your suggestion to remove $product['title'][$x], If I got stuck I will post here Thanks________________________________________________________________________________________ OFFQ : My friend told to me if better I learn java rather than PHP, he told me because in the future java is the best to build web, rather than PHP, is that correct ? please explain me (if not objection) Thanks again

Thanks for reply, A : I think I need 3 entries to show product at user. I 'll to remove some entries of $_SESSION array, if I get stuck please help me Thanks

I think I need to the point, please see this image : code on above : $count = count($_SESSION['buy']); while($x<$count){$product['title'][$x] = $_SESSION['buy'][0];$product['price'][$x] = $_SESSION['buy'][1];$product['img'][$x] = $_SESSION['buy'][2];} Q : Can I using array_unique to avoid duplicate array value like image on above? Q : If array_unique not possible, what I must do so that array value not duplicated ? please help me thanks

Hello everyone please see this code : <?$data = array();$data[0] = "test";$data[1] = "price";$data[2] = "img";$data[3] = "img";echo(array_unique($data));?> if I wrote code like on above it won't show anything, but if I using print_r it can displayed Q : Actually can I display it using echo ? So that the result shown like this : please answer Thanks

Hi everyone, please see this code : while($x<2){$product['title'][$x] = $_SESSION['buy'][0];$product['price'][$x] = $_SESSION['buy'][1];$product['img'][$x] = $_SESSION['buy'][2];} it's now result like this : it's can be shown because : (while($x<2)), Q : if product more than 2, of course I cannot using $x<2 it should be : $x<$count or $etc, how to create so that $count can be shown automatically based on ordered product ? please help me Thanks

Hi, You right, thanks for answer. But I didn't found tutorial about : $_SESSION['buy'][] = $data; Q : What the meaning of this code? on : http://w3schools.com.../php_arrays.asp On this tutorial it's not written : array should be initialized first , then you create arrays. (please see on numeric arrays example) and this the code <?php$cars[0]="Saab";$cars[1]="Volvo";$cars[2]="BMW";$cars[3]="Toyota";echo $cars[0] . " and " . $cars[1] . " are Swedish cars.";?> This is made me thought , if not necessary to initialize array ($data=array(); then , $data[0] =... and etc) please tell me Thanks

I think to initialize session as an array no need to add "array()" on session Q : So, it's must be written before I made another array? please help me Thanks

Hello, Q : Sorry, I rather don't understand can you explain me more? This my new code : Code II (buy.php) : <?require("database.php");$s = $_POST['test'];$product_db = mysql_query("select * from product where p_id='$s'");$p_list = mysql_fetch_array($product_db);$p_title = $p_list['p_title'];$p_price = $p_list['p_price'];$p_img = $p_list['p_image']; session_start();$_SESSION['pid'] = $s;$_SESSION['buy'][0] = $p_title;$_SESSION['buy'][1] = $p_price;$_SESSION['buy'][2] = $p_img;header("location: index.php?p=shop");?> This is code III (content_shop.php) : <?if($_SESSION['pid']){$x=0;while($x<2){$product['title'][$x] = $_SESSION['buy'][0];$product['price'][$x] = $_SESSION['buy'][1];$product['img'][$x] = $_SESSION['buy'][2];echo"".$product['title'][$x]."<br />".$product['price'][$x]."<br />".$product['img'][$x]."<br /><br />";$x++;}}else{echo"fail";}?> This is result from my code : And this is my expectation (this result from image modification using photoshop tool): Q : What's mistake on my code? please help me Thanks

Ok, thanks everyone, I'll try this , but if I stuck I will post here again please help me Once again , Thanks

Hello everyone, if I using this session code it cannot add product when user buy other product : Code I : <form method="post" action="buy.php"> <input type="text" value="<?$id1 = $product_id?>" style="display:none" name="test" /></div> <div class="pr" style="height:15px"><b style="font-size:14px"><?echo"$product_name";?></b></div> <div class="pr"><input type="submit" value="BUY NOW" /></div></form> //this is product 1 <form method="post" action="buy.php"> <input type="text" value="<?$id2 = $product_id2;?>" style="display:none" name="test" /></div> <div class="pr" style="height:15px"><b style="font-size:14px"><?echo"$product_name2";?></b></div> <div class="pr"><input type="submit" value="BUY NOW" /></div></form> //this is product 2 Code II (buy.php) <?require("database.php");$s = $_POST['test'];session_start();$_SESSION['$s']= $s;header("location: index.php?p=shop");?> Code III (this is page where the cart is shown content_shop.php) : <?if($_SESSION['$s']){$product_db = mysql_query("select * from product where p_id='".$_SESSION['$s']."'");$product_list = mysql_fetch_array($product_db);$product_title = $product_list['p_title'];$product_price = $product_list['p_price'];$product_img = $product_list['p_image'];echo"$product_title<br />$product_price<br />$product_img<br />".$_SESSION['total']."<br />";}else{echo"fail";}?> When I click "BUY NOW" it can added to basket cart, but when I buy other product, it changes to last product (product that last to be clicked) Q : How to display using session, all product that I had bought (on shopping cart)? please help me Thanks :

Ok, thanks for answer, but if I am stuck I will post here again.

Q : So, actually user buy first (without login) on shopping cart, it's without using database? Q : And all of the product and basket (everything) are using session? Please tell me Thanks

Hello everyone, I think all of you know about shopping cart, I had tried to create shopping cart on my site into localhost, using firefox It works, but when I open on other browser and open my localhost using it, cause my cart on firefox lost or deleted (I open two browser and test my site). Q : Is if I open my site on localhost using two different browser simultaneously it can cause session_destroy? Q : Should I upload my site to web hosting so that when I open using 2 browser simultaneously it cannot cause session_destroy? please answer Thanks

Thanks everyone

Hello everyone I found on this forum some thread that written "this topic is locked", Q : Why this thread locked? please tell me Thanks

Actually I want learn about hack site, just for protect my site from hack. But I don't know where I can found source to learn about hack site Q : Can you tell me where I can found material or source to learn hack site ? Thanks

Of course NOT!! , I ask about this because I astonished with something, But because your information I become understand now Thanks for information____________________________________________________________________________________ BTW : I am not corrupted man who do something that can harm other people , in short I never want to hurt someone. Sometimes I ask off topic just to make conversation so that not stiff. But I think lately people not like if I ask about off topic (my thought), then I seldom to ask about off topic except it's important for me. So, don't worry with me...

Hello everyone, I ever heard from my friends, if there is someone who deliberately pay hacker to hack a site. Is that true? please tell me Thanks

I didn't said without form, just if <input> or button change to <a> I ask this question because this tag won't work on IE6 : <a href="/../"><input type="button" value="cancel" /></a> I can use <input type="image" src="" /> but I should create image for it, But alright this okay . Thanks for answer

Hello everyone, Please read this simple code : <form name="" action="" method="post"><input type="submit" value="submit" /> //or<button>SUBMIT</button></form> Usually people using <input > tag to create "SUBMIT" button or using <button></button> to create it, like on above. Q : If I using tag : <a href=""></a> can I create submit button ? Please answer Thanks

My question really not about on array, but it's about how to display session, this : <?if($_SESSION['user'][0][1][2][3][4]){echo"that's good";}else{echo"hello";}?> and this : <?if($_SESSION['user']){echo"that's good";}else{echo"hello";} //then if($_SESSION['user'][0]){echo"that's good";}else{echo"hello";} if($_SESSION['user'][1]){echo"that's good";}else{echo"hello";} //etc...?> from both on above, which one is correct? (that's my question). I know, of course the second option is the answer, if I using array Q : But if I using array in session repeatedly (like on second option), it's can be run or it's just redundant?

Q : if the session had given value, still it can given array? For example : <?$_SESSION['user'] = $user; // then I give it array -----> (1)$_SESSION['user'] = array();$_SESSION['user'][0] = $member;$_SESSION['user'][1] = $another_ thing;$_SESSION['user'][2] = 'hello';$_SESSION['user'][3] = 'cookie';$_SESSION['user'][4] = 'please_help_me'; // and finally, to display session : -----> (2) if($_SESSION['user'][0][1][2][3][4]){echo"that's good";}else{echo"hello";} //or -----> (3) if($_SESSION['user']){echo"that's good";}else{echo"hello";} //then if($_SESSION['user'][0]){echo"that's good";}else{echo"hello";} if($_SESSION['user'][1]){echo"that's good";}else{echo"hello";} //etc...?> Q : Code on above which is correct? Q : Number : -----> (2) or -----> (3) ?? thanks

Hello everyone, Yesterday when I'am online at about 11.45 pm (this forum time). I can't access this forum suddenly, why?Till I can't post my thread I had try to check my connection and reopen this site but it can't connect. please tell me thanks

Q : Array? did you mean I can use array more than 1 like this code : <?php$_SESSION['v1'][1] = 'cake'; //or if($_SESSION['test']['member']){//some php code...}?> Note : I got this example from : http://php.net/manua...les.session.php please tell me Thanks