Joey46 Posted March 18, 2009 Share Posted March 18, 2009 This is my PHP code below$CourseNumber = $_POST['CourseNumber'];$CourseName = $_POST['CourseName'];$StudyMode = $_POST['StudyMode'];// assemble the sql query string to insert a record$query = "INSERT INTO Courses(CourseNumber, CourseName, StudyMode,) VALUES ('CourseNumber', '$CourseName', '$StudyMode')"; // open a connection and select the database$conn = mysql_connect($host, $username, $password);@mysql_select_db($database, $conn) or die( "Unable to select $database database"); // add the recordif(mysql_query($query, $conn)){ echo "Record added successfully!";}else{ echo "Something went wrong. MySQL reports: <b>", mysql_error(), "</b>";} mysql_close($conn); // reuse the previous forminclude("Courseadd.htm");?>This is my HTML code<h2 align="center">Add Course</h2> <form method="post" action="Courseadd.php"><table width="450" border="5" align="center" cellpadding="5" bordercolor="#CCCCCC"> <tr> <td width="150">CourseNumber</td> <td width="300"><input type="text" name="CourseNumber_ID" /> </td> </tr> <tr> <td>CourseName </td> <td><input type="text" name="CourseName" /></td> </tr> <tr> <td>StudyMode</td> <td><input type="text" name="StudyMode" /></td> </tr> <tr> <td><input type="reset" name="Reset" value="Cancel" /></td> <td><input type="submit" name="Submit" value="Add Course" /></td> </tr></table> </form><p> </p><div align="center"> </div></form>This is the ERROR MSGSomething went wrong. MySQL reports: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ') VALUES ('CourseNumber', 'Diploma', 'flex')' at li Link to comment Share on other sites More sharing options...
ProblemHelpPlease Posted March 18, 2009 Share Posted March 18, 2009 You need to change the variable as below, had not included the $ for CourseNumber // assemble the sql query string to insert a record$query = "INSERT INTO Courses(CourseNumber, CourseName, StudyMode,)VALUES ('$CourseNumber', '$CourseName', '$StudyMode')"; Link to comment Share on other sites More sharing options...
mohammad_molana Posted March 18, 2009 Share Posted March 18, 2009 whit is this page name?and you shoud do this:<?phpif(isset($_POST['CourseNumber'])){ //insert to mysql}else{ // show form}?>for form's action you should write nothing to post data to page self Link to comment Share on other sites More sharing options...
Joey46 Posted March 18, 2009 Author Share Posted March 18, 2009 You need to change the variable as below, had not included the $ for CourseNumber// assemble the sql query string to insert a record$query = "INSERT INTO Courses(CourseNumber, CourseName, StudyMode,)VALUES ('$CourseNumber', '$CourseName', '$StudyMode')"; You were right of course but when i tired it after fixing it i still get this errorSomething went wrong. MySQL reports: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ') VALUES ('', 'Diploma', 'flex')' at line 1 Link to comment Share on other sites More sharing options...
Ingolme Posted March 18, 2009 Share Posted March 18, 2009 Most likely, being a number field, you shouldn't have quotes around $CourseNumber in the query. Link to comment Share on other sites More sharing options...
Joey46 Posted March 18, 2009 Author Share Posted March 18, 2009 Most likely, being a number field, you shouldn't have quotes around $CourseNumber in the query.This is my php script now$CourseNumber = $_POST['CourseNumber'];$CourseName = $_POST['CourseName'];$StudyMode = $_POST['StudyMode'];// assemble the sql query string to insert a record$query = "INSERT INTO Courses (CourseNumber, CourseName, StudyMode,)"; "VALUES ($CourseNumber, '$CourseName', '$StudyMode')"; // open a connection and select the database$conn = mysql_connect($host, $username, $password);@mysql_select_db($database, $conn) or die( "Unable to select $database database"); // add the recordif(mysql_query($query, $conn)){ echo "Record added successfully!";}else{ echo "Something went wrong. MySQL reports: <b>", mysql_error(), "</b>";} mysql_close($conn);This is now the error msgSomething went wrong. MySQL reports: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')' at line 1 Link to comment Share on other sites More sharing options...
Ingolme Posted March 18, 2009 Share Posted March 18, 2009 You have an extra comma in the query. Anyways, you haven't added the "VALUES" part into the query. Here's what it should be like: $query = "INSERT INTO Courses (CourseNumber, CourseName, StudyMode) VALUES ($CourseNumber, '$CourseName', '$StudyMode')"; Link to comment Share on other sites More sharing options...
Joey46 Posted March 18, 2009 Author Share Posted March 18, 2009 You have an extra comma in the query. Anyways, you haven't added the "VALUES" part into the query. Here's what it should be like:$query = "INSERT INTO Courses (CourseNumber, CourseName, StudyMode) VALUES ($CourseNumber, '$CourseName', '$StudyMode')"; This is what i am getting back nowSomething went wrong. MySQL reports: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' 'diploma', 'flex')' at line 1 so then i played around with it and it says added now so it is fixed thankyou for your help much appreciated mate Link to comment Share on other sites More sharing options...
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