newphpcoder Posted March 10, 2011 Share Posted March 10, 2011 Good day!I want to know what is wrong in my code that's why when i choose in select option it did not go to another page...Like when I select "Incoming" nothing happen also when I choose "Outgoing" nothing also happen.Here is my code: <?phpinclude ("config.php");$call_type = $_POST['call_type'];$query=mysql_query("SELECT `call_type` FROM `tbl_calltype` WHERE `call_type` = '{$call_type}'") or die(mysql_error());$result = mysql_num_rows($query);if ($result == 1){if($call_type == 'Incoming'){ header ('Location:incoming.php');}elseif($call_type == 'Outgoing'){ header ('Location:outgoing.php');}else{ header('Location:index.php');}}?><html><body><form id="form1" name="form1" method="post" action=""> <select name="call_type"> <option value="Select Call Type">Select Call Type</option> <option value="Incoming" <?php if($_POST['call_type'] == 'Incoming') echo "selected='selected'"; ?>>Incoming</option> <option value="Outgoing" <?php if($_POST['call_type'] == 'Outgoing') echo "selected='selected'"; ?>>Outgoing</option> </select></form></body></html> Thank you Link to comment Share on other sites More sharing options...
[dx] Posted March 10, 2011 Share Posted March 10, 2011 Well.. You must use select onchange. But I'm not sure what. Maybe onchange="submit" or this.submit Link to comment Share on other sites More sharing options...
thescientist Posted March 10, 2011 Share Posted March 10, 2011 you can either use Javascript to bind an event handler to the select element to detect changes in the list, or use an actual submit button to submit the form to the page and catch the selected option and redirect with PHP. Either way you need an event to fire to initiate any sort of action on the page. Link to comment Share on other sites More sharing options...
thescientist Posted March 10, 2011 Share Posted March 10, 2011 n/m Link to comment Share on other sites More sharing options...
newphpcoder Posted March 11, 2011 Author Share Posted March 11, 2011 n/mI tried this code:<?php include ("config.php"); if (isset($_POST['call_type'])) { // Check if form has been submitted $call_type = mysql_real_escape_string($_POST['call_type']); // SECURE THE FECKING CONTENT!!!!!!!!!!!!!!!!!!!!!! echo $call_type; $query=mysql_query("SELECT `call_type` FROM `tbl_calltype` WHERE `call_type` = '{$call_type}'") or die(mysql_error()); $result = mysql_num_rows($query); echo '<br />' . $result;/*if ($result == 1){ if($call_type == 'Incoming'){ header ('Location:incoming.php'); } elseif($call_type == 'Outgoing'){ header ('Location:outgoing.php'); } else{ header('Location:index.php'); } }*/} ?> <html> <body> <form id="form1" name="form1" method="post" action=""> <select name="call_type"> <option value="Select Call Type">Select Call Type</option> <option value="Incoming" <?php if($_POST['call_type'] == 'Incoming') echo "selected='selected'"; ?>>Incoming</option> <option value="Outgoing" <?php if($_POST['call_type'] == 'Outgoing') echo "selected='selected'"; ?>>Outgoing</option> </select> <input type="submit" name = "Submit" value="Submit"> </form> </body> </html> As you can see I add submit button.The output of this code isv , when I choose Incoming and i press submit button the result is Incoming 1 and it was displayed in the same page. I want to happen is when I choose Incoming and I press submit button it will go to incoming.php:cry:Thank you Link to comment Share on other sites More sharing options...
birbal Posted March 11, 2011 Share Posted March 11, 2011 i think your php is outputing (eg echo $call_type;)in the page before its been redirecting. probably there an warning is occuring "header already been sent" to be sure you may want to make all error enabled to display. (may be its not displaying for your php.ini setting)when its ouput something in browser headers are already been sent so in later you cant resend the header again. you can do that though with output bufferring.i can see you commented the redirected part hope its uncommented in your real scirpt Link to comment Share on other sites More sharing options...
thescientist Posted March 11, 2011 Share Posted March 11, 2011 if you want to use headers, you can't have ANY output before you set the headers, so get rid of the echo'shttp://us.php.net/manual/en/function.header.php <?php include ("config.php"); if (isset($_POST['call_type'])) { // Check if form has been submitted $call_type = mysql_real_escape_string($_POST['call_type']); // SECURE THE FECKING CONTENT!!!!!!!!!!!!!!!!!!!!!! echo $call_type; $query=mysql_query("SELECT `call_type` FROM `tbl_calltype` WHERE `call_type` = '{$call_type}'") or die(mysql_error()); $result = mysql_num_rows($query); echo '<br />' . $result;/*if ($result == 1){ if($call_type == 'Incoming'){ header ('Location:incoming.php'); } elseif($call_type == 'Outgoing'){ header ('Location:outgoing.php'); } else{ header('Location:index.php'); } }*/} ?> Link to comment Share on other sites More sharing options...
newphpcoder Posted March 14, 2011 Author Share Posted March 14, 2011 if you want to use headers, you can't have ANY output before you set the headers, so get rid of the echo'shttp://us.php.net/manual/en/function.header.php I tried this code:<?phpinclude ("config.php"); if (isset($_POST['call_type'])) { // Check if form has been submitted $call_type = mysql_real_escape_string($_POST['call_type']); // SECURE THE FECKING CONTENT!!!!!!!!!!!!!!!!!!!!!! $query=mysql_query("SELECT `call_type` FROM `tbl_calltype` WHERE `call_type` = '{$call_type}'") or die(mysql_error()); $result = mysql_num_rows($query); if ($result == 1){ if($call_type == 'Incoming'){ header ('Location:incoming.php'); } elseif($call_type == 'Outgoing'){ header ('Location:outgoing.php'); } else{ header('Location:index.php'); } }} ?><html> <body> <form id="form1" name="form1" method="post" action=""> <select name="call_type" onchange="return handleEnter(this, event)"> <option value="Select Call Type">Select Call Type</option> <option value="Incoming" <?php if($_POST['call_type'] == 'Incoming') echo "selected='selected'"; ?>>Incoming</option> <option value="Outgoing" <?php if($_POST['call_type'] == 'Outgoing') echo "selected='selected'"; ?>>Outgoing</option> </select> <input type="submit" name = "Submit" value="Submit"></form> </body> </html> And the output is nothing was happened when I choose incoming.php Link to comment Share on other sites More sharing options...
Ingolme Posted March 14, 2011 Share Posted March 14, 2011 You need to do some debugging. Check what $call_type and $result are.Location headers are supposed to be absolute URIs. // Is $result what I expected it to be? echo '$result: ' . $result . '<br>'; if ($result == 1) { // Is $call_type what I expected it to be? echo '$call_type: ' . $call_type . '<br>'; // Headers commented while testing values if($call_type == 'Incoming') { // Location headers must be an absolute URI: // header ('Location: http://' $_SERVER['SERVER_NAME'] . dir($_SERVER['PHP_SELF']) . 'incoming.php'); } elseif($call_type == 'Outgoing') { // header ('Location: http://' $_SERVER['SERVER_NAME'] . dir($_SERVER['PHP_SELF']) . 'outgoing.php'); } else { // header ('Location: http://' $_SERVER['SERVER_NAME'] . dir($_SERVER['PHP_SELF']) . 'index.php'); } } Link to comment Share on other sites More sharing options...
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