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'ajaxRequest' is null or not an object


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Hi....I have form which I put save function on the last textbox:here is my code:

<?php    error_reporting(0);   date_default_timezone_set("Asia/Singapore"); //set the time zone $con = mysql_connect('localhost', 'root','');if (!$con) {    echo 'failed';    die();}mysql_select_db("mes", $con);?><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html><head><script type="text/javascript" > var input_size = 1;function checkTextBox(bc){   var barcode_ =  bc.tabIndex;     if ( bc.value.length > input_size )	    {		    for(i=0; i<document.barcode.elements.length; i++)		    {					  if( document.barcode.elements[i].tabIndex == (barcode_+1) )					 {   						 document.barcode.elements[i].focus();						 break;					 }		  }    }		}function postSet() {    if (window.event.keyCode==13 || window.event.keyCode==10) {	    document.getElementById('code_read_box6').disabled = true;	    save();	    alert('code_read_box6');    }} </script><script type="text/javascript">var ajaxTimeOut = null;var ajaxTimeOutOperator = null;var responsePHP; // = "no_reply"var responsePHPOperator;var changeFocus; //= false;var transactionWasSaved;function remoteRequestObject() {    var ajaxRequest = false;    try {	    ajaxRequest = new XMLHttpRequest();    }    catch(err) {	    try{		    ajaxRequest = new ActiveXObject("MSxml2.XMLHTTP");	    }	    catch(err) {		    try{			    ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");		    }		    catch(err){			    // --> change to DOM alert("Not Supported Browser") + err.description;			    notify('Not Supported Browser.');			    return false;		    }	    }    }    return ajaxRequest;}var ajaxRequest; // = remoteRequestObject();var ajaxRequestOperator;</script><script type="text/javascript">function save() {		       ajaxRequest.onreadystatechange = function () {    if (ajaxRequest.readyState==4 && ajaxRequest.status==200) {	   var result = ajaxRequest.responseText;	  	    alert (result);		  		   if (result == "failed") {		    document.getElementById('code_read_box6').disabled = false;		    document.getElementById('code_read_box6').value = "";		    document.getElementById('code_read_box6').focus();		    notify("Please scan again.");		   }		  		   if (result == "saved") {			  alert(result);			  notify("Transaction has been saved.");			  reset();		   }  		  	   }	    }	       var url = "save_barcode.php";  ajaxRequest.open("POST", url, true);ajaxRequest.setRequestHeader("Content-type", "application/x-www-form-urlencoded");ajaxRequest.setRequestHeader("Content-length", parameters.length);ajaxRequest.setRequestHeader("Connection", "close");ajaxRequest.send(parameters);} </script> </head><body onLoad="document.barcode.code_read_box1.focus();"><form name="barcode" ><input type="text" tabindex="1" id="code_read_box1" value="" onkeyup="checkTextBox(this);"/><br/><input type="text" tabindex="2" id="code_read_box2" value="" onkeyup="checkTextBox(this);"/><br/><input type="text" tabindex="3" id="code_read_box3" value="" onkeyup="checkTextBox(this);"/><br/><input type="text" tabindex="4" id="code_read_box4" value="" onkeyup="checkTextBox(this);"/><br/><input type="text" tabindex="5" id="code_read_box5" value="" onkeyup="checkTextBox(this);"/><br/><input type="text" tabindex="6" id="code_read_box6" value="" onkeyup="checkTextBox(this);" onkeypress="postSet()"/><br/></form></body> </html>

I got an error:'ajaxRequest' is null or not an object on line 72It display the error when I press enter on the last textbox.Sorry, I'm not familiar in ajax..I hope somebody can help meThank you

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