Badchip Posted October 17, 2015 Share Posted October 17, 2015 I have a website with some TV channels. One of them have 3 variable URL's (.m3u8), only works 1 URL at day, it's random. http://mdsiosgeo1-lh.akamaihd.net/i/mitele/esmediaset_11@168495/index_0_av-b.m3u8 http://mdsios1-lh.akamaihd.net/i/mitele/esmediaset_11@168471/index_0_av-p.m3u8 http://mdsios2-lh.akamaihd.net/i/mitele/esmediaset_21@168473/index_0_av-p.m3u8 I'd like to click the channel/button/icon in order to open automatically the working URL. Thank you in advance. Link to comment Share on other sites More sharing options...
justsomeguy Posted October 19, 2015 Share Posted October 19, 2015 How are you supposed to know which URL works if it's random? Link to comment Share on other sites More sharing options...
Badchip Posted October 20, 2015 Author Share Posted October 20, 2015 (edited) How are you supposed to know which URL works if it's random? No idea, I thought maybe there is a way to test/validate each one and open the working URL. Try to open the 3 URL's. One of them can download the "m3u8" file, the rest shows the message: "An error occurred while processing your request." Edited October 20, 2015 by Badchip Link to comment Share on other sites More sharing options...
justsomeguy Posted October 20, 2015 Share Posted October 20, 2015 I suppose you can try sending ajax requests to each of them if that server allows cross-domain ajax requests, and then check the response headers to look for an error or something else that would indicate a problem.http://help.dottoro.com/ljxsrgqe.phpIf the server doesn't allow cross-domain ajax requests then you'll need to send an ajax request to a local file like a PHP script that can send the requests and check the headers. Link to comment Share on other sites More sharing options...
Badchip Posted October 29, 2015 Author Share Posted October 29, 2015 I suppose you can try sending ajax requests to each of them if that server allows cross-domain ajax requests, and then check the response headers to look for an error or something else that would indicate a problem.http://help.dottoro.com/ljxsrgqe.phpIf the server doesn't allow cross-domain ajax requests then you'll need to send an ajax request to a local file like a PHP script that can send the requests and check the headers. The problem is I have no idea of programming. Some kind soul can help me out? I guess it's easy for any programmer. Link to comment Share on other sites More sharing options...
justsomeguy Posted October 29, 2015 Share Posted October 29, 2015 Well, if someone wants to take on the work for free, I won't stop them. Otherwise, we're here to help people learn how to program if that's what you want to do. Link to comment Share on other sites More sharing options...
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