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setTimeout method


dedyandy
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From a call of setTimeout("moveText(" + x + "," + y + ")", 1), could anybody help why the first parameter of setTimeout method takes the form of " + x + "," + y + "? Why not setTimeout(“moveText(x,y)”, 1)?Please note that x and y are used as numbers in moveText function.Thanks,Andy

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From a call of setTimeout("moveText(" + x + "," + y + ")", 1), could anybody help why the first parameter of setTimeout method takes the form of " + x + "," + y + "? Why not setTimeout(“moveText(x,y)”, 1)?Please note that x and y are used as numbers in moveText function.Thanks,Andy

The reason for why you have to take the form " + x + "," + y + " is simple. The setTimeout function stores the first parameter as a string, the x and y are variables. So when the function moveText function is called, it is called anonymously, so the variables x and y are not going to be available to it. So you have to give it values for the parameters instead of variable references.Hope this helps!
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Yes is because the function is stored as a string, this is to stop it from executing immediately rather than at the setTimeOut, so the string must be ended to insert a variable and so forth.

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