anand.arjunan Posted November 2, 2006 Share Posted November 2, 2006 Hi all i got a print_r($_FILES);output is Array ( [file_1] => Array ( [name] => [type] => [tmp_name] => [error] => 4 => 0 ) [file_0] => Array ( [name] => AT.jpg [type] => image/pjpeg [tmp_name] => /tmp/php5K8RLS [error] => 0 => 3481 ) ) here how to get "AT.jpg" separatelymy coding is <form name="exap" enctype="multipart/form-data" method = "post"> <!-- The file element -- NOTE: it has an ID --> <input id="my_file_element" type="file" name="file_1[]" > <input type="button" onClick="return frm_sub();" value="submit"></form>............... Link to comment Share on other sites More sharing options...
justsomeguy Posted November 2, 2006 Share Posted November 2, 2006 If you look at the source code that displays line breaks, the output of print_r looks more like this: Array ( [file_1] => Array ( [name] => [type] => [tmp_name] => [error] => 4 [size] => 0 ) [file_0] => Array ( [name] => AT.jpg [type] => image/pjpeg [tmp_name] => /tmp/php5K8RLS [error] => 0 [size] => 3481 ) ) To access, for example, the name AT.jpg, it would be $_FILES['file_0']['name']. Link to comment Share on other sites More sharing options...
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