Opening a link in PHP

[judacoor]

Hey everyoneI'm having problems trying to load a new php file, I don't really know how.Here's the thing: I have a login and password input form on one page, wich sends the info to itself after being submitted.So what I do is that everytime the page loads, it first checks if there are $_POST variables available, if there aren't it just loads the form normally to input those variables; if the username and pw are present and are correct as well I want to load the next page, where the user is logged in.But I don't know how open/load a new php file.I tryed using < aref .....<\a> or something like that, but I can't seem to make it work.Please help!!

[Jamess]

Hey everyoneI'm having problems trying to load a new php file, I don't really know how.Here's the thing: I have a login and password input form on one page, wich sends the info to itself after being submitted.So what I do is that everytime the page loads, it first checks if there are $_POST variables available, if there aren't it just loads the form normally to input those variables; if the username and pw are present and are correct as well I want to load the next page, where the user is logged in.But I don't know how open/load a new php file.I tryed using < aref .....<\a> or something like that, but I can't seem to make it work.Please help!!

<meta http-equiv="refresh" content="1;url=http://google.co.uk">1 represents the number of seconds before your new page will load. After url= should be the full (not relative) adress of your file.. just to keep it simple!

[judacoor]

Jamess:I've tryed it, but it shows the following error:Parse error: syntax error, unexpected '<'What would it be?

[teng84]

can i see the code

[judacoor]

<?php include('../Connections/conn2.php');$login= $_POST["user"];$pw = $_POST["pw"];$link=Connection();//A function within conn2.phpif($login!=null&&$pw!=null){ $result = mysql_query("SELECT * FROM `users` WHERE `users`.`login` = '$login'",$link); if($result!=null){ while($row = mysql_fetch_array($result)){ if($row["password"]==$pw){ session_start(); $_SESSION['id_user']=$row["id_user"]; <meta http-equiv="refresh" content="1;url=http://localhost/TestSite/menu.php"> } else{ echo "User NOT found","<br>"; } } else{ echo "Usuario NO encontrado","<br>"; }}?>But I can't get it to open the new link, after the server verifies the user name and password!!!!What can I do???

[teng84]

<?phpsession_start();include('../Connections/conn2.php');$login= $_POST["user"];$pw = $_POST["pw"];$link=Connection();//A function within conn2.phpif($login!=null&&$pw!=null){$result = mysql_query("SELECT * FROM `users` WHERE `users`.`login` = '$login'",$link); $row = mysql_fetch_assoc($result); if($row["password"]==$pw) { $_SESSION['id_user']=$row["id_user"]; header('location:http://localhost/TestSite/menu.php'); exit(); }}?> hoooo you alot of error try that first then add some missing litle by litle to avoid from breaking down that code

[justsomeguy]

You can't just write HTML in the code. You have to use echo or print to send text.echo "<meta http-equiv=\"refresh\" content=\"1;url=http://localhost/TestSite/menu.php\">";

[judacoor]

Thanks guysThat has really helped me out!!