php Challenged

[george]

Where $key and $item are valid text variables containing valid values, Why does this work?

echo "$key. $item<br />\n";

I thought the correct code would be

echo $key . $item . "<br />\n";

Is php responding to the $ to render the value of the variable even when it is within quotes? I thought that by being in quotes, it would render the literal value of what is quoted, and not the variable content.

[Kristian_C]

why it works well, just becouse it is the right way to use it, you chould use :

echo"$key . $item .\"<br>\n\""; //but why do you have the \n actually? <br> works just fine dont it?

Dont actually understand what the whole challenge thing was about ..-Kristian_C

[justsomeguy]

When a string is in double-quotes or heredoc syntax PHP will do variable replacement and replace the non-escaped variables with their values. If the string is single-quoted PHP will not do variable replacement.http://www.php.net/manual/en/language.types.string.php