Jump to content

What's with the function Left()?


Seeker
 Share

Recommended Posts

Why does the expression strHx = left(s,inStr(s,",")-1) cause the error message Invalid procedure call or argument: 'left', while the expression strHx = left(s,inStr(s,",")+1) does not? I want to parse the string s and bring back everything to the left of the first comma. Any help would be appreciated.

Link to comment
Share on other sites

strHx = left(s,inStr(s,",")-1)Works fine for me.  Why not:strHx =  split(s,",")(0)though?

I think I understand what's going on here. If no comma is found in s, the Left() function would get -1 as the second argument, which may cause some problems, I guess. I'll have to Replace() the comma with nothing.Thanks for your response, Blue. I don't know why it works for you, maybe version differences. I'm not sure how to get the version number for my IIS server, but the under the Default Website Properties, on the Server Extensions tab, I see version 4.0.2.6513.
Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
 Share

×
×
  • Create New...