simple dynamic variable question

[niche]

I need to create an array and name it dynamically.Here's the script I tried to use (unsuccessfully):

$counter = 1; $a.$counter = array(current($_POST));echo var_dump($a$counter);echo '</br>';echo var_dump($a1);echo '</br>';

This produces a parse error.Please, what am I doing wrong?Thanks

[niche]

I thing I get it! See: http://php.net/manual/en/language.variables.variable.phpAm this far:

$counter = 1; $a = 'a' . $counter;$$a = array(current($_POST));echo '</br>';echo var_dump($a1);

I'll check back if I get off the path.

[Synook]

Creating variables like that is generally not the best option - have you considered using a multidimensional array?P.S. the break tag is empty, and is just written <br> (or <br /> in XHTML).

[jeffman]

Assuming you really do need a variable variable, that is the way to do it. As you discovered, variable identifiers cannot be concatenated like strings, because they are not really strings.The only 'exception' is array indexes, which can behave like strings. Example:$arr['a1'] = 'Hello';$ord1 = 'a';$ord2 = '1';echo $arr[$ord1 . $ord2]; // 'Hello'

[wirehopper]

<?php$b='b is 1';$vVariable='b';echo $$vVariable.PHP_EOL;$$vVariable='b is 2';echo $b.PHP_EOL;