rewrite links to use referer script

[AzaraT]

Hi,What I want to do is to take a link like this http://test.com and make it into http.//www.mydomain.com/redirect.php?site=test.comI got my data in a string (they need to be submitted to a database). So I've tried using str_replace like this:

$content2 = str_replace("http://", "http.//www.mydomain.com/redirect.php?mid={$msg_id}&site=", $content);

however what I get from this is a link to

http://localhost:8888/%22http://www.mydomain.com/redirect.php?site=test.com\%22

Which I really dont get (note I'm currently testing on my localhost..)Someone can help me get this done correctly? Thanks a lotJacob / AzaraT

[justsomeguy]

Have you printed $content to see what it is? It looks like str_replace is either not running, not finding the text to replace, or you're doing something else with $content2. The reason I say that is because str_replace tells it to add a querystring variable called mid, but that doesn't show up in what you printed.

[ApocalypeX]

Here is your problem$content2 = str_replace("http://", "http.//www.mydomain.com/redirect.php?mid={$msg_id}&site=", $contentYou put a period instead of a colon.

[AzaraT]

For some reason I didn't get a notification email before today about the replys.Meanwhile I found a solution:

function callback($match) {	global $msg_id;return "http://www.mydomain.com/redirect.php?mid=" . $msg_id . "&&site=" . parse_url($match[1], PHP_URL_HOST);}$content = '<a href="http://test.com">test</a> <p> Other html code here blablabla </p>';//this is where the changes take effect...$content = preg_replace_callback('~(http://[^ "]+)~i', 'callback', $content);

Thanks anyway