My Function Is Not Called When Button Is Clicked.

[chitchirya]

Good day!This is my first time to post here in forums. Sorry for my bad english.Hopefully you can help me with my problem. This is my Function

function showResult(class){alert(class);}

This is my Php code;

do{   echo "<input type='button' value=".$result['class_name']." name=".$result['class_name']." onclick='showResult(this.value)'>";   $result = mysql_fetch_assoc($query);  }while($result);

My button seems working properly but when I call the function during the event onClick, it does not work. Please help me. God bless all =)

[justsomeguy]

You should have quotes around the value and name, and you might need to use a function like str_replace to replace quotes with HTML entities.

[chitchirya]

It has already,

value=".$result['class_name']." name=".$result['class_name']."

its, inside a php code.

[justsomeguy]

The quotes don't get printed in the HTML, they are quotes in PHP code. Look at the HTML that the code creates to see what actually gets sent to the browser.

[chitchirya]

Do you mean like this?

value='".$result['class_name']."' name='".$result['class_name']."'

It does not work also. but why this code work...

<select name=".addslashes($result['skill_name'])." onChange='showRlvl(this.value,this.name);   showEffect(this.value,this.name,".$result['skill_id']."); showPoints2(this.value)'>

[chitchirya]

Lol! Made it working, I just added id=".$result['class_name']." btw, thanks alot for helping =) EDIT: also, variable class makes my code don't work so I made another variable in which javascript variables is not used. Sigh. Another lesson learned. =)

[tutorholic]

I think class is a javascript keyword.It cannot be used as variable names

[thescientist]

I think class is a javascript keyword.It cannot be used as variable names