substr V str_replace

[westman]

hi there am trying to print out a string and if the string is more then 20 then the end will be cut and replaced with "..."this is what i have so fare $name = substr ($name, 0, 20);i can cut any string to 20 no prob but how do i add "..." at the end if the string is more than 20?

[Ingolme]

Check strlen().

$e = '';if(strlen($str) > 20) {    $e = '...';}$output = substr($str, 0, 20);$output .= $e;

[westman]

thank you so much it works well

[birbal]

..also you can do like

$output = str_pad(substr($str, 0, 20),23,'...',STR_PAD_RIGHT);

http//php.net/str_pad If you are doing this for visual cliping of textual content. there is CSS option for that http://w3schools.com/cssref/css3_pr_text-overflow.asp

[justsomeguy]

Here's a version that supports UTF characters:

function str_maxwidth($str, $w){  return (mb_strlen($str, 'UTF-8') <= $w ? $str : (substr_unicode($str, 0, $w - 3) . '...'));}function substr_unicode($str, $s, $l = null){  // stolen from the php.net manual page for mb_substr  return join("", array_slice(preg_split("//u", $str, -1, PREG_SPLIT_NO_EMPTY), $s, $l));}

Call str_maxwidth with the string and maximum length.