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Multiply File Upload


SimonGillham
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I have the below HTML and PHP code for uploading multiple files, but for some reason only 1 file is being uploaded. Does anyone know why?

Many Thanks

Simon

<!DOCTYPE html>
<html>
<body>

<form action="upload.php" method="post" enctype="multipart/form-data">
    Select image to upload:
    
<input type="file" name="fileToUpload" id="fileToUpload" multiple>
    <input type="submit" value="Upload Image" name="submit">
</form>

</body>
</html>

 

The PHP is

<?php
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = strtolower(pathinfo($target_file,PATHINFO_EXTENSION));
// Check if image file is a actual image or fake image
if
(isset($_POST["submit"])) {
    $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
    if($check !== false) {
        echo "File is an image - " . $check["mime"] . ".";
        $uploadOk = 1;
    } else {
        echo "File is not an image.";
        $uploadOk = 0;
    }
}

// Check if file already exists
if
 (file_exists($target_file)) {
    echo "Sorry, file already exists.";
    $uploadOk = 0;
}
// Check file size
if
 ($_FILES["fileToUpload"]["size"] > 500000) {
    echo "Sorry, your file is too large.";
    $uploadOk = 0;
}
// Allow certain file formats
if
($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
&& $imageFileType != "gif" ) {
    echo "Sorry, only JPG, JPEG, PNG & GIF files are allowed.";
    $uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if
 ($uploadOk == 0) {
    echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} 
else {
    if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
        echo "The file ". basename( $_FILES["fileToUpload"]["name"]). " has been uploaded.";
    } else {
        echo "Sorry, there was an error uploading your file.";
    }
}

?>

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If I remember correctly, if you change the name of the input to "fileToUpload[]" it should arrive as an array in PHP.

If that worked correctly, on the server side the $_FILES array actually has the indices on the second component. Instead of $_FILES["fileToUpload"][0]["size"] you actually have to access $_FILES["fileToUpload"]["size"][0].

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Because its not an image, its an array of images, you need to setup a foreach loop to get each image file

foreach ($_FILES["fileToUpload"]["name"] as $index => $imageFile) {
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"][$index]);

...


}

Every $_FILES["fileToUpload"]["?????"] within foreach loop has to end with [$index] as shown above, this tell it what image in the array is being processed.

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